Quantitative Ability – POINTS TO REMEMBER
1.If an equation (i.e. f(x) = 0) contains all positive co-efficients of any powers of x, it has no positive roots.
Eg: x^3+3x^2+2x+6=0 has no positive roots
2.For an equation, if all the even powers of x have same sign coefficients and all the odd powers of x have the opposite sign coefficients, then it has no negative roots.
3.For an equation f(x)=0 , the maximum number of positive roots it can have is the number of sign changes in f(x) ; and the maximum number of negative roots it can have is the number of sign changes in f(-x)
4.Complex roots occur in pairs, hence if one of the roots of an equation is 2+3i, another has to be
2-3i and if there are three possible roots of the equation, we can conclude that the last root is real. This real root could be found out by finding the sum of the roots of the equation and subtracting (2+3i)+(2-3i)=4 from that sum.
5.For a cubic equation ax^3+bx^2+cx+d=o
Sum of the roots = - b/a
Sum of the product of the roots taken two at a time = c/a
Product of the roots = -d/a
6.For a bi-quadratic equation ax^4+bx^3+cx^2+dx+e = 0
Sum of the roots = - b/a
Sum of the product of the roots taken two at a time = c/a
Sum of the product of the roots taken three at a time = -d/a
Product of the roots = e/a
7.If an equation f(x)= 0 has only odd powers of x and all these have the same sign coefficients or if f(x) = 0 has only odd powers of x and all these have the same sign coefficients, then the equation has no real roots in each case (except for x=0 in the second case)
8.Consider the two equations
a1x+b1y=c1
a2x+b2y=c2
Then,
If a1/a2 = b1/b2 = c1/c2, then we have infinite solutions for these equations.
If a1/a2 = b1/b2 <> c1/c2, then we have no solution.
If a1/a2 <> b1/b2, then we have a unique solution.
9.a + b = a + b if a*b>=0
else, a + b >= a + b
10.The equation ax^2+bx+c=0 will have max. value when a<0>0. The max. or min. value is given by (4ac-b^2)/4a and will occur at x = -b/2a
11.If for two numbers x + y=k (a constant), then their PRODUCT is MAXIMUM if x=y (=k/2). The maximum product is then (k2)/4.
12. If for two numbers x*y=k (a constant), then their SUM is MINIMUM if x=y (=root(k)). The minimum sum is then 2*root (k).
13.Product of any two numbers = Product of their HCF and LCM. Hence product of two numbers = LCM of the numbers if they are prime to each other.
14. For any 2 numbers a, b where a>b
a>AM>GM>HM>b (where AM, GM ,HM stand for arithmetic, geometric , harmonic means respectively)
(GM)^2 = AM * HM
15.For three positive numbers a, b, c
(a + b + c) * (1/a + 1/b + 1/c)>=9
16.For any positive integer n
2<= (1 + 1/n)^n <=3
17. a^2 + b^2 + c^2 >= ab + bc + ca
If a=b=c, then the case of equality holds good.
18.a^4 + b^4 + c^4 + d^4 >= 4abcd (Equality arises when a=b=c=d=1)
19.(n!)^2 > n^n
20.If a + b + c + d=constant, then the product a^p * b^q * c^r * d^s will be maximum if a/p = b/q = c/r = d/s
21.x^n -a^n = (x-a)(x^(n-1) + x^(n-2) + .......+ a^(n-1) ) ......Very useful for finding multiples. For example (17-14=3 will be a multiple of 17^3 - 14^3)
22.e^x = 1 + (x)/1! + (x^2)/2! + (x^3)/3! + ........to infinity
Note: 2 < e < 3
23.log(1+x) = x - (x^2)/2 + (x^3)/3 - (x^4)/4 .........to infinity [Note the alternating sign . .Also note that the logarithm is with respect to base e]
24.(m + n)! is divisible by m! * n!
25.When a three digit number is reversed and the difference of these two numbers is taken, the middle number is always 9 and the sum of the other two numbers is always 9.
26.Any function of the type y=f(x)=(ax-b)/(bx-a) is always of the form x=f(y)
The sum of first n natural numbers = n(n+1)/2
The sum of squares of first n natural numbers is n(n+1)(2n+1)/6
The sum of cubes of first n natural numbers is (n(n+1)/2)2/4
The sum of first n even numbers= n (n+1)
The sum of first n odd numbers= n^2
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Quantitative Ability – POINTS TO REMEMBER(Algebra)
Test on numbers(10Q)
DIRECTIONS for Questions 1 and 2: Answer the questions on the basis of the information given below.
N is a natural number such that 300 < N < 750. P is the sum of the number N and the number formed by reversing the digits of N, even if upon reversing, it becomes a two-digit or a single-digit number. P is also equal to ‘K’ times the sum of the digits of the number N.
1. Find the minimum possible value of ‘K’.
1. 28.5 2. 32.75 3. 37.5 4. 40.25 5. 43.5
2. If ‘K’ = (96*4)/17, then find the remainder when N is divided by the sum of its digits.
1. 9 2. 12 3. 11 4. 5 5. 6
3. What is the product of all factors of the number N = 6^4 * 10^2 which are divisible by 5?
2^210 * 3^102 * 5^140
2^210 * 3^140 * 5^105
2^140 * 3^210 * 5^102
2^140 * 3^102 * 5^210
2^102 * 3^210 * 5^140
4 .If the product of four positive integers is 10! Then what is the smallest possible value their sum can have?
1. 180 2. 181 3. 175 4. 176 5 . 174
5. 3^36 – 1 = 1A009463A296999120, where A is a single digit whole number, then the value of A is
1. 1 2. 2 3. 8 4. 5 5. 6
6. Out of the 200 even natural numbers. How many even numbers exit having even number of factors?
1. 90 2. 10 3. 190 4. None of these
7. Let d1,d2….dk be all the factors of a positive integer n in ascending order including 1 and n. Supposed d1+d2+d1……..+dk = 72
Then the value of 1/d1 + 1/d2 + 1/d3……….+1/dk is
1. N^2/ 72 2. N/72 3. 72/n 4.d36/ n
8. N = 2^15* 3^7* 5^10 . How many factors of N are multiples of 360 but not multiples of 10800?
1. 402 2. 240 3. 204 4. 420
9. A = 626!-625! How many consecutive zeros would be there at the end of A?
1. 156 2. 160 3. 1 4. None of these
10. A = 4^86 – 2^171. How many digits would be there in binary notation of A?
1. 171 2. 172 3. 87 4. 88
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