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Test on numbers(10Q)

DIRECTIONS for Questions 1 and 2: Answer the questions on the basis of the information given below.
N is a natural number such that 300 < N < 750. P is the sum of the number N and the number formed by reversing the digits of N, even if upon reversing, it becomes a two-digit or a single-digit number. P is also equal to ‘K’ times the sum of the digits of the number N.

1. Find the minimum possible value of ‘K’.
1. 28.5 2. 32.75 3. 37.5 4. 40.25 5. 43.5

2. If ‘K’ = (96*4)/17, then find the remainder when N is divided by the sum of its digits.

1. 9 2. 12 3. 11 4. 5 5. 6

3. What is the product of all factors of the number N = 6^4 * 10^2 which are divisible by 5?
2^210 * 3^102 * 5^140
2^210 * 3^140 * 5^105
2^140 * 3^210 * 5^102
2^140 * 3^102 * 5^210
2^102 * 3^210 * 5^140

4 .If the product of four positive integers is 10! Then what is the smallest possible value their sum can have?

1. 180 2. 181 3. 175 4. 176 5 . 174

5. 3^36 – 1 = 1A009463A296999120, where A is a single digit whole number, then the value of A is

1. 1 2. 2 3. 8 4. 5 5. 6

6. Out of the 200 even natural numbers. How many even numbers exit having even number of factors?

1. 90 2. 10 3. 190 4. None of these

7. Let d1,d2….dk be all the factors of a positive integer n in ascending order including 1 and n. Supposed d1+d2+d1……..+dk = 72
Then the value of 1/d1 + 1/d2 + 1/d3……….+1/dk is

1. N^2/ 72 2. N/72 3. 72/n 4.d36/ n

8. N = 2^15* 3^7* 5^10 . How many factors of N are multiples of 360 but not multiples of 10800?

1. 402 2. 240 3. 204 4. 420


9. A = 626!-625! How many consecutive zeros would be there at the end of A?

1. 156 2. 160 3. 1 4. None of these

10. A = 4^86 – 2^171. How many digits would be there in binary notation of A?

1. 171 2. 172 3. 87 4. 88

4 Responses to "Test on numbers(10Q)"

Anonymous (visit their site)

1) option 4
2)
3) option 2
4) option 1 (used hit n trial)
5)
6) option 3
7) option 3
8) option 2
9) option 2
10) option 2

Anonymous (visit their site)

5) option 4

Amol (visit their site)

Hi ankit
well done...
only quesion no 4 answer was not correct.
concept require of maxima minima...

bishweshwar (visit their site)

amol sir,

did not get through Q1. please tell the approach.

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